Quadratic trinomial

Oskemen Nurorda school-lyceum

Date: 

Teacher’s name: Assel Dosmakhan

Grade: 8А

Number present:

Number absent: 

Theme of the lesson:

Quadratic equation

Learning objectives

8.2.1.2 To allocate a complete square of the binomial of the trinomial;

8.2.1.3 Decompose a square polynomial;

Lesson objectives

All learners will be able to:

• Find roots of trinomial;

• Decompose a trinomial.

Lesson structure

Planned timings

Teacher activity

Student

activity

Evaluation

Resources

Beginning

The lesson greeting.

The teacher sets the lesson objectives, 

letting students know what to anticipate from the lesson.

Lead-in.

Then to create a positive learning environment the teacher asks students

to start the lesson giving each other compliments about appearance, job performance, talent, etc. and also practice accepting compliments.

Students greet the teacher

Give each other compliments 

Individual evaluation

Verbal evaluation

Course book

Middle

Exercise 1

Factorize the square trinomial

х²-8х+15; х²-11х+30 ; 3х²-5х-8;

х²-16х+60; х²+20х-96; 3х²+4х-7;

х²-4х-77 ; х²+10х-24; -9х²+8х+1;

х²+5х-14 ; х²-4х-96 ; 5х²+2х-3;

5х²-10х-15 ; 5х²+9х-2; х²-21х+110;

Exercise 2

Level tasks/Simplify/Pair work

1-row 2-row 3-row

Exercise 3

Matching

They will factorize quadratic equations

х²-8х+15=(x-3)(x-5)

х²-11х+30=(x-5)(x-6)

3х²-5х-8=(x+1)(3x-8)

х²-16х+60=(x-6)(x-10)

х²+20х-96=(x+24)(x-4)

3х²+4х-7=(3x-7)(x-1)

х²-4х-77=(x+7)(x-11)

х²+10х-24=(x+12)(x-2)

-9х²+8х+1=(-x+1)(9x+1)

х²+5х-14=(x+7)(x-2)

х²-4х-96=(x+8)(x-12)

5х²+2х-3=5(x+1)(x-3)

5х²-10х-15=5(x+1)(x-3)

5х²+9х-2=(x+2)(5x-1)

х²-21х+110=(x-10)(x-11)

Students will factorize and will simplify trinomials.

Students match each equation with their name .

Individual evaluation

Mutual evaluation

 PPTWhiteboard

Cards

End

Reflection

«Instagram assessment » method

- like it

- see it

- want to live comments

Sts reflect the lesson

Peer assessment